Check Armstrong Number of N digits

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#include <stdio.h>
#include <math.h>
int arm(int a)
{
    int i=0,res=0,dup,rem;
    dup=a;
    while(dup!=0)
    {
       dup= dup/10;
        ++i;  // To find how many digits present
    }
    dup=a;
    while(dup!=0)
    {
        rem=dup%10;
        res+=pow(rem,i);
        dup=dup/10;
    }
    return res;
}
int main()
{
    int n,c;
    scanf("%d",&n);
    c=arm(n);
    if(c==n)
    {
        printf("armstrong number");
    }
    else
    {
        printf("not a armstrong number");
    }
    

    return 0;
}